设An为正项数列,Sn为前n项和,且An,Sn,An^2成等差数列.

2025-12-15 16:32:51
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回答1:

Sn=(An+ An^2)/2
An=Sn-Sn-1=(An+ An^2)/2-(An-1+ An-1^2)/2
得(An+An-1)(An-An-1-1)=0,An为正项
An=An-1+1,A1=S1=(A1+ A1^2)/2,A1=1
An=n
1/A1A2+1/A2A3+......+1/AnAn+1=1/1*2+1/2*3+......+1/n*n+1
=1-1/2+1/2-1/3+……+1/n-1/n+1
=1-1/n+1<1