解一个不等式。。4x^2+12x+9小于等于0

4x^2+12x+9小于等于0希望给出过程。。谢谢啦!
2025-12-14 21:53:43
推荐回答(3个)
回答1:

4x^2+12x+9小于等于0
(2x)^2+2*4x*3+3^2≤0
(2x+3)^2≤0
因对任意x, (2x+3)^2≥0
所以只有唯一的2x+3=0
解得x=-3/2
希望能帮到你O(∩_∩)O

回答2:

4x^2+12x+9小于等于0
4x^2+12x+9<=0
(2x+3)^2<=0
2x+3>=0 2x+3<=0
x>=-3/2 x<=-3/2
x=-3/2

回答3:

4x^2+12x+9<=0
(2x+3)^2<=0
则2x+3=0
x=-3/2