用简便方法计算
2013²-2012²
解,得:
==(2013+2012)(2013-2012)
==2025*1
==2025
(x²+y²)²-4x²y²,当x=3.5,y=1.5
解,得:
==[(x²+y²)+2xy][(x²+y²)-2xy]
==(x+y)^2(x-y)^2
把x=3.5,y=1.5带入(x+y)^2(x-y)^2,得:
==(3.5+1.5)^2(3.5-1.5)^2
==25*4
==100
2013²-2012²
=(2013-2012)(2013+2012)
=4025
(x²+y²)²-4x²y²
=x^4+2x^2y^2+y^4-4x^2y^2
=x^4-2x^2y^2+y^4
=(x^2-y^2)^2
=(x-y)^2(x+y)^2
=(3.5-1.5)^2(3.5+1.5)^2
=(2^2)*(5^2)
=100
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2013²-2012²
=(2013+2012)×(2013-2012)
=4025×1
=4025
(x²+y²)²-4x²y²
=(x²+y²+2xy)(x²+y²-2xy)
=(x+y)²(x-y)²
=(3.5+1.5)²×(3.5-1.5)²
=25×4
=100
2013²-2012²=(2013+2012)(2013-2012)=4025;
(x²+y²)²-4x²y²=(x²+y²+2xy)(x²+y²-2xy)=(x+y)²(x-y)²=5²2²=100